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limn 无穷

当n→无穷,1/(n^2+n+1)+2/(n^2+n+2)++n/(n^2+n+n)≤1/(n^2+n+1)+2/(n^2+n+1)++n/(n^2+n+1)=(1+2++n)/(n^2+n+1)=(1/2)(n+1)n/(n^2+n+1)-> 1/21/(n^2+n+1)+2/(n^2+n

这是取极限的运算符号,是n趋近于无穷时,某个关于n的式子的极限的意思,例如limn-无穷时,1/n趋近于0.

这道题你只要换个思维想,n趋于无穷,1/n 就趋于0,lim 1/n 趋于0,分子分同除以n^3分子为 (n+1)(n+2)(n+3)* 1/n *1/n*1/n=(1+1/n)(1+2/n)(1+3/n)分母为5+(1/n)^2答案应为3/5

用定积分定义如图计算该极限,答案是ln2.经济数学团队帮你解答,请及时采纳.

=limn趋近于无穷[(n+1)(n+2)/2]/n^2=limn趋近于无穷(n^2+3n+2)/[2n^2]分子分母同除以n^2所以最后极限就=1/2

lim (n^2+n)/4N^2=1/4

n/(1+n)=1/[1+(1/n)]=1/(1+0)=1 lim n趋近于无穷 n/n+1=1

(1/n+1)/(1/n)=n/n+1 lim=1lim1/n+1=lim1/n=0(n+1)!/n!=n+1 lim=+无穷

Iimn无穷等于you的意思是你的力量是无穷尽的

[1/1*3+1/3*5+……+1/(2n-1)(2n+1)] =1/2[1-1/3+1/3-1/5++1/(2n-1)+1/(2n+1]= 1/2[1+1/(2n+1)]所以Limn趋于无穷1/2*[1+/(2n+1)]=1/2

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